Base | Representation |
---|---|
bin | 1010000001000011111100… |
… | …0011011110011011101010 |
3 | 1102222212101120121022112022 |
4 | 2200100333003132123222 |
5 | 2420420322112211014 |
6 | 35231244234344442 |
7 | 2214455115411035 |
oct | 240207703363352 |
9 | 42885346538468 |
10 | 11013354022634 |
11 | 3566812256857 |
12 | 129a565b8b122 |
13 | 61b729c59bb2 |
14 | 2a1098d3801c |
15 | 141738c3ba8e |
hex | a043f0de6ea |
11013354022634 has 4 divisors (see below), whose sum is σ = 16520031033954. Its totient is φ = 5506677011316.
The previous prime is 11013354022597. The next prime is 11013354022669. The reversal of 11013354022634 is 43622045331011.
11013354022634 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 10830003064609 + 183350958025 = 3290897^2 + 428195^2 .
It is a junction number, because it is equal to n+sod(n) for n = 11013354022594 and 11013354022603.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2753338505657 + ... + 2753338505660.
Almost surely, 211013354022634 is an apocalyptic number.
11013354022634 is a deficient number, since it is larger than the sum of its proper divisors (5506677011320).
11013354022634 is an equidigital number, since it uses as much as digits as its factorization.
11013354022634 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5506677011319.
The product of its (nonzero) digits is 51840, while the sum is 35.
Adding to 11013354022634 its reverse (43622045331011), we get a palindrome (54635399353645).
The spelling of 11013354022634 in words is "eleven trillion, thirteen billion, three hundred fifty-four million, twenty-two thousand, six hundred thirty-four".
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