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110134023 = 336711341
BaseRepresentation
bin1101001000010…
…00001100000111
321200020101110220
412210020030013
5211143242043
614532315423
72505060306
oct644101407
9250211426
10110134023
115719335a
1230a72b73
1319a8137c
14108ac43d
159a07483
hex6908307

110134023 has 4 divisors (see below), whose sum is σ = 146845368. Its totient is φ = 73422680.

The previous prime is 110134001. The next prime is 110134039. The reversal of 110134023 is 320431011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 110134023 - 213 = 110125831 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110133993 and 110134011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110134093) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18355668 + ... + 18355673.

It is an arithmetic number, because the mean of its divisors is an integer number (36711342).

Almost surely, 2110134023 is an apocalyptic number.

110134023 is a deficient number, since it is larger than the sum of its proper divisors (36711345).

110134023 is an equidigital number, since it uses as much as digits as its factorization.

110134023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36711344.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 110134023 is about 10494.4758325511. The cubic root of 110134023 is about 479.3365008090.

Adding to 110134023 its reverse (320431011), we get a palindrome (430565034).

The spelling of 110134023 in words is "one hundred ten million, one hundred thirty-four thousand, twenty-three".

Divisors: 1 3 36711341 110134023