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11013434311 = 111001221301
BaseRepresentation
bin10100100000111001…
…11010101111000111
31001102112201102122111
422100130322233013
5140023414344221
65020504041451
7536631434635
oct122034725707
931375642574
1011013434311
114741884230
122174463287
13106694c449
147669aa355
15446d44be1
hex29073abc7

11013434311 has 4 divisors (see below), whose sum is σ = 12014655624. Its totient is φ = 10012213000.

The previous prime is 11013434279. The next prime is 11013434321. The reversal of 11013434311 is 11343431011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11013434311 - 25 = 11013434279 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11013434321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 500610640 + ... + 500610661.

It is an arithmetic number, because the mean of its divisors is an integer number (3003663906).

Almost surely, 211013434311 is an apocalyptic number.

11013434311 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

11013434311 is a deficient number, since it is larger than the sum of its proper divisors (1001221313).

11013434311 is a wasteful number, since it uses less digits than its factorization.

11013434311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1001221312.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 11013434311 its reverse (11343431011), we get a palindrome (22356865322).

The spelling of 11013434311 in words is "eleven billion, thirteen million, four hundred thirty-four thousand, three hundred eleven".

Divisors: 1 11 1001221301 11013434311