Base | Representation |
---|---|
bin | 1010000001000110011101… |
… | …1011100001000010101111 |
3 | 1102222221010210020100000001 |
4 | 2200101213123201002233 |
5 | 2420423214020212143 |
6 | 35231435353245131 |
7 | 2214510652215223 |
oct | 240214733410257 |
9 | 42887123210001 |
10 | 11014031413423 |
11 | 356702a663555 |
12 | 129a714a037a7 |
13 | 61b8073b134c |
14 | 2a1120ca8783 |
15 | 14177844514d |
hex | a04676e10af |
11014031413423 has 4 divisors (see below), whose sum is σ = 11094425803440. Its totient is φ = 10933637023408.
The previous prime is 11014031413409. The next prime is 11014031413487. The reversal of 11014031413423 is 32431413041011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11014031413423 - 29 = 11014031412911 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11014031413391 and 11014031413400.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11014031419423) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40197194803 + ... + 40197195076.
It is an arithmetic number, because the mean of its divisors is an integer number (2773606450860).
Almost surely, 211014031413423 is an apocalyptic number.
11014031413423 is a deficient number, since it is larger than the sum of its proper divisors (80394390017).
11014031413423 is an equidigital number, since it uses as much as digits as its factorization.
11014031413423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 80394390016.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 11014031413423 its reverse (32431413041011), we get a palindrome (43445444454434).
The spelling of 11014031413423 in words is "eleven trillion, fourteen billion, thirty-one million, four hundred thirteen thousand, four hundred twenty-three".
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