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110141213443 = 611805593663
BaseRepresentation
bin110011010010011101…
…1011000101100000011
3101112021221010100210121
41212210323120230003
53301032122312233
6122333112241111
710646254603312
oct1464473305403
9345257110717
10110141213443
114278a930938
121941a0a0197
13a503840661
14548bc62279
152ce96dd92d
hex19a4ed8b03

110141213443 has 4 divisors (see below), whose sum is σ = 111946807168. Its totient is φ = 108335619720.

The previous prime is 110141213437. The next prime is 110141213447. The reversal of 110141213443 is 344312141011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 344312141011 = 907379616473.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110141213443 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (110141213447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 902796771 + ... + 902796892.

It is an arithmetic number, because the mean of its divisors is an integer number (27986701792).

Almost surely, 2110141213443 is an apocalyptic number.

110141213443 is a deficient number, since it is larger than the sum of its proper divisors (1805593725).

110141213443 is an equidigital number, since it uses as much as digits as its factorization.

110141213443 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1805593724.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 110141213443 its reverse (344312141011), we get a palindrome (454453354454).

The spelling of 110141213443 in words is "one hundred ten billion, one hundred forty-one million, two hundred thirteen thousand, four hundred forty-three".

Divisors: 1 61 1805593663 110141213443