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11014212555251 = 17800161877251
BaseRepresentation
bin1010000001000111001000…
…1110100001000111110011
31102222221121102002021212122
42200101302032201013303
52420424101403232001
635231505343544455
72214515312000423
oct240216216410763
942887542067778
1011014212555251
113567112936044
12129a7655bb12b
1361b835a94b69
142a113ad7c483
151417892c6b1b
hexa04723a11f3

11014212555251 has 4 divisors (see below), whose sum is σ = 11014274610504. Its totient is φ = 11014150500000.

The previous prime is 11014212555211. The next prime is 11014212555257. The reversal of 11014212555251 is 15255521241011.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11014212555251 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11014212555257) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30760625 + ... + 31116626.

It is an arithmetic number, because the mean of its divisors is an integer number (2753568652626).

Almost surely, 211014212555251 is an apocalyptic number.

11014212555251 is a deficient number, since it is larger than the sum of its proper divisors (62055253).

11014212555251 is an equidigital number, since it uses as much as digits as its factorization.

11014212555251 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62055252.

The product of its (nonzero) digits is 20000, while the sum is 35.

Adding to 11014212555251 its reverse (15255521241011), we get a palindrome (26269733796262).

The spelling of 11014212555251 in words is "eleven trillion, fourteen billion, two hundred twelve million, five hundred fifty-five thousand, two hundred fifty-one".

Divisors: 1 178001 61877251 11014212555251