Search a number
-
+
11014444135 = 52202888827
BaseRepresentation
bin10100100001000001…
…10001010001100111
31001102121121201212101
422100200301101213
5140024144203020
65020541432531
7536643142012
oct122040612147
931377551771
1011014444135
1147424039a2
12217486b747
131066c13c86
14766b90379
15446e9400a
hex290831467

11014444135 has 4 divisors (see below), whose sum is σ = 13217332968. Its totient is φ = 8811555304.

The previous prime is 11014444081. The next prime is 11014444157. The reversal of 11014444135 is 53144441011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53144441011 = 109487563679.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11014444135 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1101444409 + ... + 1101444418.

It is an arithmetic number, because the mean of its divisors is an integer number (3304333242).

Almost surely, 211014444135 is an apocalyptic number.

11014444135 is a deficient number, since it is larger than the sum of its proper divisors (2202888833).

11014444135 is an equidigital number, since it uses as much as digits as its factorization.

11014444135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2202888832.

The product of its (nonzero) digits is 3840, while the sum is 28.

Adding to 11014444135 its reverse (53144441011), we get a palindrome (64158885146).

The spelling of 11014444135 in words is "eleven billion, fourteen million, four hundred forty-four thousand, one hundred thirty-five".

Divisors: 1 5 2202888827 11014444135