Base | Representation |
---|---|
bin | 11001000011101000111110… |
… | …000111010111111000110101 |
3 | 112110012010211222110211101122 |
4 | 121003220332013113320311 |
5 | 103421014242112013023 |
6 | 1030213441224033325 |
7 | 32132532161013053 |
oct | 3103507607277065 |
9 | 473163758424348 |
10 | 110201313001013 |
11 | 321281292794a3 |
12 | 10439904902845 |
13 | 4964c2962b0c0 |
14 | 1d2dab45691d3 |
15 | cb18c80942c8 |
hex | 643a3e1d7e35 |
110201313001013 has 8 divisors (see below), whose sum is σ = 122770693529400. Its totient is φ = 98216554822848.
The previous prime is 110201313001001. The next prime is 110201313001051. The reversal of 110201313001013 is 310100313102011.
It can be written as a sum of positive squares in 4 ways, for example, as 24235909308004 + 85965403693009 = 4922998^2 + 9271753^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 110201313001013 - 212 = 110201312996917 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 110201313000982 and 110201313001000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (110201313001063) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 146155587158 + ... + 146155587911.
It is an arithmetic number, because the mean of its divisors is an integer number (15346336691175).
Almost surely, 2110201313001013 is an apocalyptic number.
110201313001013 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
110201313001013 is a deficient number, since it is larger than the sum of its proper divisors (12569380528387).
110201313001013 is a wasteful number, since it uses less digits than its factorization.
110201313001013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 292311175111.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 110201313001013 its reverse (310100313102011), we get a palindrome (420301626103024).
The spelling of 110201313001013 in words is "one hundred ten trillion, two hundred one billion, three hundred thirteen million, one thousand, thirteen".
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