Base | Representation |
---|---|
bin | 10000000010011100010… |
… | …000001011000100011001 |
3 | 10220100210112220010211010 |
4 | 100002130100023010121 |
5 | 121024132034104423 |
6 | 2202151333324133 |
7 | 142424612614134 |
oct | 20023420130431 |
9 | 3810715803733 |
10 | 1102133113113 |
11 | 39545945649a |
12 | 159726196649 |
13 | 7cc139bb096 |
14 | 3b4b48d321b |
15 | 1da07da9693 |
hex | 1009c40b119 |
1102133113113 has 32 divisors (see below), whose sum is σ = 1488116972160. Its totient is φ = 725513564160.
The previous prime is 1102133113099. The next prime is 1102133113117. The reversal of 1102133113113 is 3113113312011.
It is not a de Polignac number, because 1102133113113 - 24 = 1102133113097 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1102133113113.
It is not an unprimeable number, because it can be changed into a prime (1102133113117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 236659281 + ... + 236663937.
It is an arithmetic number, because the mean of its divisors is an integer number (46503655380).
Almost surely, 21102133113113 is an apocalyptic number.
It is an amenable number.
1102133113113 is a deficient number, since it is larger than the sum of its proper divisors (385983859047).
1102133113113 is a wasteful number, since it uses less digits than its factorization.
1102133113113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7737.
The product of its (nonzero) digits is 162, while the sum is 21.
Adding to 1102133113113 its reverse (3113113312011), we get a palindrome (4215246425124).
The spelling of 1102133113113 in words is "one trillion, one hundred two billion, one hundred thirty-three million, one hundred thirteen thousand, one hundred thirteen".
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