Base | Representation |
---|---|
bin | 10100100001111000… |
… | …00111100110010001 |
3 | 1001110010002222022211 |
4 | 22100330013212101 |
5 | 140033013112312 |
6 | 5021355232121 |
7 | 540061111561 |
oct | 122074074621 |
9 | 31403088284 |
10 | 11021613457 |
11 | 4746460358 |
12 | 2177148641 |
13 | 106855428a |
14 | 767ad8da1 |
15 | 44790d3a7 |
hex | 290f07991 |
11021613457 has 4 divisors (see below), whose sum is σ = 11135238436. Its totient is φ = 10907988480.
The previous prime is 11021613443. The next prime is 11021613467. The reversal of 11021613457 is 75431612011.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1950193921 + 9071419536 = 44161^2 + 95244^2 .
It is a cyclic number.
It is not a de Polignac number, because 11021613457 - 219 = 11021089169 is a prime.
It is a super-3 number, since 3×110216134573 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11021613467) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56812344 + ... + 56812537.
It is an arithmetic number, because the mean of its divisors is an integer number (2783809609).
Almost surely, 211021613457 is an apocalyptic number.
It is an amenable number.
11021613457 is a deficient number, since it is larger than the sum of its proper divisors (113624979).
11021613457 is an equidigital number, since it uses as much as digits as its factorization.
11021613457 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 113624978.
The product of its (nonzero) digits is 5040, while the sum is 31.
The spelling of 11021613457 in words is "eleven billion, twenty-one million, six hundred thirteen thousand, four hundred fifty-seven".
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