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11022001314 = 231837000219
BaseRepresentation
bin10100100001111011…
…00110010010100010
31001110010211200100220
422100331212102202
5140033113020224
65021411423510
7540064315422
oct122075462242
931403750326
1011022001314
1147466a57a5
1221772b4b96
13106865b98c
14767b9a482
15447988279
hex290f664a2

11022001314 has 8 divisors (see below), whose sum is σ = 22044002640. Its totient is φ = 3674000436.

The previous prime is 11022001313. The next prime is 11022001337. The reversal of 11022001314 is 41310022011.

It is a sphenic number, since it is the product of 3 distinct primes.

11022001314 is an admirable number.

It is a junction number, because it is equal to n+sod(n) for n = 11022001293 and 11022001302.

It is not an unprimeable number, because it can be changed into a prime (11022001313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 918500104 + ... + 918500115.

It is an arithmetic number, because the mean of its divisors is an integer number (2755500330).

Almost surely, 211022001314 is an apocalyptic number.

11022001314 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11022001314 is a wasteful number, since it uses less digits than its factorization.

11022001314 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1837000224.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 11022001314 its reverse (41310022011), we get a palindrome (52332023325).

The spelling of 11022001314 in words is "eleven billion, twenty-two million, one thousand, three hundred fourteen".

Divisors: 1 2 3 6 1837000219 3674000438 5511000657 11022001314