11022121113 has 4 divisors (see below), whose sum is σ = 14696161488. Its totient is φ = 7348080740.

The previous prime is 11022121087. The next prime is 11022121129. The reversal of 11022121113 is 31112122011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11022121113 - 2¹³ = 11022112921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11022121092 and 11022121101.

It is not an unprimeable number, because it can be changed into a prime (11022121133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1837020183 + ... + 1837020188.

It is an arithmetic number, because the mean of its divisors is an integer number (3674040372).

Almost surely, 2^11022121113 is an apocalyptic number.

It is an amenable number.

11022121113 is a deficient number, since it is larger than the sum of its proper divisors (3674040375).

11022121113 is an equidigital number, since it uses as much as digits as its factorization.

11022121113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3674040374.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 11022121113 its reverse (31112122011), we get a palindrome (42134243124).

The spelling of 11022121113 in words is "eleven billion, twenty-two million, one hundred twenty-one thousand, one hundred thirteen".