Base | Representation |
---|---|
bin | 1010000001101000010010… |
… | …1011010000000011110111 |
3 | 1110000210120121222112111201 |
4 | 2200122010223100003313 |
5 | 2421100313133341043 |
6 | 35235540414113331 |
7 | 2215251664064506 |
oct | 240320453200367 |
9 | 43023517875451 |
10 | 11023112012023 |
11 | 356a96a3a46a1 |
12 | 12a0429aab847 |
13 | 61c623771307 |
14 | 2a1742ca083d |
15 | 141b0a742c4d |
hex | a0684ad00f7 |
11023112012023 has 4 divisors (see below), whose sum is σ = 11024716781160. Its totient is φ = 11021507242888.
The previous prime is 11023112012021. The next prime is 11023112012051. The reversal of 11023112012023 is 32021021132011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11023112012023 - 21 = 11023112012021 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11023112012021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 802374265 + ... + 802388002.
It is an arithmetic number, because the mean of its divisors is an integer number (2756179195290).
Almost surely, 211023112012023 is an apocalyptic number.
11023112012023 is a deficient number, since it is larger than the sum of its proper divisors (1604769137).
11023112012023 is an equidigital number, since it uses as much as digits as its factorization.
11023112012023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1604769136.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 11023112012023 its reverse (32021021132011), we get a palindrome (43044133144034).
The spelling of 11023112012023 in words is "eleven trillion, twenty-three billion, one hundred twelve million, twelve thousand, twenty-three".
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