Base | Representation |
---|---|
bin | 1010000001101000101101… |
… | …1011110011100010100011 |
3 | 1110000210212112100102110002 |
4 | 2200122023123303202203 |
5 | 2421101031200403210 |
6 | 35235555544330215 |
7 | 2215254541643201 |
oct | 240321333634243 |
9 | 43023775312402 |
10 | 11023225403555 |
11 | 356aa18402402 |
12 | 12a045ba7396b |
13 | 61c6410c32b1 |
14 | 2a1753d7a071 |
15 | 141b156904a5 |
hex | a068b6f38a3 |
11023225403555 has 16 divisors (see below), whose sum is σ = 13275266292288. Its totient is φ = 8786984640000.
The previous prime is 11023225403513. The next prime is 11023225403573. The reversal of 11023225403555 is 55530452232011.
It is not a de Polignac number, because 11023225403555 - 28 = 11023225403299 is a prime.
It is a super-2 number, since 2×110232254035552 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 85121855 + ... + 85251255.
It is an arithmetic number, because the mean of its divisors is an integer number (829704143268).
Almost surely, 211023225403555 is an apocalyptic number.
11023225403555 is a deficient number, since it is larger than the sum of its proper divisors (2252040888733).
11023225403555 is a wasteful number, since it uses less digits than its factorization.
11023225403555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 190318.
The product of its (nonzero) digits is 180000, while the sum is 38.
Adding to 11023225403555 its reverse (55530452232011), we get a palindrome (66553677635566).
The spelling of 11023225403555 in words is "eleven trillion, twenty-three billion, two hundred twenty-five million, four hundred three thousand, five hundred fifty-five".
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