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110243000341 = 1721019374351
BaseRepresentation
bin110011010101011111…
…1101011000000010101
3101112120000122200011201
41212222333223000111
53301234202002331
6122351150032501
710651632020155
oct1465277530025
9345500580151
10110243000341
1142832332941
12194481a8731
13a51b95b5a6
14549b59a765
152d035e7a61
hex19aafeb015

110243000341 has 12 divisors (see below), whose sum is σ = 117224585280. Its totient is φ = 103656017600.

The previous prime is 110243000323. The next prime is 110243000377. The reversal of 110243000341 is 143000342011.

It is not a de Polignac number, because 110243000341 - 215 = 110242967573 is a prime.

It is a super-2 number, since 2×1102430003412 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110243000381) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 107316 + ... + 481666.

It is an arithmetic number, because the mean of its divisors is an integer number (9768715440).

Almost surely, 2110243000341 is an apocalyptic number.

It is an amenable number.

110243000341 is a deficient number, since it is larger than the sum of its proper divisors (6981584939).

110243000341 is a wasteful number, since it uses less digits than its factorization.

110243000341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 375404 (or 375387 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 110243000341 its reverse (143000342011), we get a palindrome (253243342352).

The spelling of 110243000341 in words is "one hundred ten billion, two hundred forty-three million, three hundred forty-one", and thus it is an aban number.

Divisors: 1 17 289 1019 17323 294491 374351 6363967 108187439 381463669 6484882373 110243000341