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110245234115 = 522049046823
BaseRepresentation
bin110011010101100100…
…0001100010111000011
3101112120011212011100002
41212223020030113003
53301240234442430
6122351305550215
710651660012502
oct1465310142703
9345504764302
10110245234115
1142833619135
1219448aa536b
13a51c261253
14549b9bc839
152d038d9845
hex19ab20c5c3

110245234115 has 4 divisors (see below), whose sum is σ = 132294280944. Its totient is φ = 88196187288.

The previous prime is 110245234103. The next prime is 110245234129. The reversal of 110245234115 is 511432542011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 511432542011 = 2272253006793.

It is a cyclic number.

It is not a de Polignac number, because 110245234115 - 220 = 110244185539 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11024523407 + ... + 11024523416.

It is an arithmetic number, because the mean of its divisors is an integer number (33073570236).

Almost surely, 2110245234115 is an apocalyptic number.

110245234115 is a deficient number, since it is larger than the sum of its proper divisors (22049046829).

110245234115 is an equidigital number, since it uses as much as digits as its factorization.

110245234115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22049046828.

The product of its (nonzero) digits is 4800, while the sum is 29.

Adding to 110245234115 its reverse (511432542011), we get a palindrome (621677776126).

The spelling of 110245234115 in words is "one hundred ten billion, two hundred forty-five million, two hundred thirty-four thousand, one hundred fifteen".

Divisors: 1 5 22049046823 110245234115