Base | Representation |
---|---|
bin | 110011010101100100… |
… | …0001100010111000011 |
3 | 101112120011212011100002 |
4 | 1212223020030113003 |
5 | 3301240234442430 |
6 | 122351305550215 |
7 | 10651660012502 |
oct | 1465310142703 |
9 | 345504764302 |
10 | 110245234115 |
11 | 42833619135 |
12 | 19448aa536b |
13 | a51c261253 |
14 | 549b9bc839 |
15 | 2d038d9845 |
hex | 19ab20c5c3 |
110245234115 has 4 divisors (see below), whose sum is σ = 132294280944. Its totient is φ = 88196187288.
The previous prime is 110245234103. The next prime is 110245234129. The reversal of 110245234115 is 511432542011.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 511432542011 = 227 ⋅2253006793.
It is a cyclic number.
It is not a de Polignac number, because 110245234115 - 220 = 110244185539 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11024523407 + ... + 11024523416.
It is an arithmetic number, because the mean of its divisors is an integer number (33073570236).
Almost surely, 2110245234115 is an apocalyptic number.
110245234115 is a deficient number, since it is larger than the sum of its proper divisors (22049046829).
110245234115 is an equidigital number, since it uses as much as digits as its factorization.
110245234115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22049046828.
The product of its (nonzero) digits is 4800, while the sum is 29.
Adding to 110245234115 its reverse (511432542011), we get a palindrome (621677776126).
The spelling of 110245234115 in words is "one hundred ten billion, two hundred forty-five million, two hundred thirty-four thousand, one hundred fifteen".
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