Base | Representation |
---|---|
bin | 1010000010000001111101… |
… | …0110110110011110100101 |
3 | 1110001110100210220021112020 |
4 | 2200200133112312132211 |
5 | 2421203421014201013 |
6 | 35243040224413353 |
7 | 2215614506630112 |
oct | 240403726663645 |
9 | 43043323807466 |
10 | 11030002100133 |
11 | 35728856a7895 |
12 | 12a1831477259 |
13 | 620181073023 |
14 | 2a1bd7da9909 |
15 | 141db059a623 |
hex | a081f5b67a5 |
11030002100133 has 16 divisors (see below), whose sum is σ = 15571842860160. Its totient is φ = 6920752214016.
The previous prime is 11030002100113. The next prime is 11030002100141. The reversal of 11030002100133 is 33100120003011.
11030002100133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11030002100133 - 230 = 11028928358309 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11030002100113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14141808 + ... + 14901366.
It is an arithmetic number, because the mean of its divisors is an integer number (973240178760).
Almost surely, 211030002100133 is an apocalyptic number.
It is an amenable number.
11030002100133 is a deficient number, since it is larger than the sum of its proper divisors (4541840760027).
11030002100133 is a wasteful number, since it uses less digits than its factorization.
11030002100133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1044316.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 11030002100133 its reverse (33100120003011), we get a palindrome (44130122103144).
The spelling of 11030002100133 in words is "eleven trillion, thirty billion, two million, one hundred thousand, one hundred thirty-three".
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