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11030031213 = 33676677071
BaseRepresentation
bin10100100010111000…
…01110101101101101
31001110200221122022120
422101130032231231
5140042141444323
65022255503153
7540222501255
oct122134165555
931420848276
1011030031213
11475018a783
122179b27ab9
13106a2108b6
14768c8a965
154485225e3
hex29170eb6d

11030031213 has 4 divisors (see below), whose sum is σ = 14706708288. Its totient is φ = 7353354140.

The previous prime is 11030031209. The next prime is 11030031247. The reversal of 11030031213 is 31213003011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11030031213 - 22 = 11030031209 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11030031192 and 11030031201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11030031203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1838338533 + ... + 1838338538.

It is an arithmetic number, because the mean of its divisors is an integer number (3676677072).

Almost surely, 211030031213 is an apocalyptic number.

It is an amenable number.

11030031213 is a deficient number, since it is larger than the sum of its proper divisors (3676677075).

11030031213 is an equidigital number, since it uses as much as digits as its factorization.

11030031213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3676677074.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 11030031213 its reverse (31213003011), we get a palindrome (42243034224).

The spelling of 11030031213 in words is "eleven billion, thirty million, thirty-one thousand, two hundred thirteen".

Divisors: 1 3 3676677071 11030031213