Base | Representation |
---|---|
bin | 1010000010000011000111… |
… | …1001010101110011011111 |
3 | 1110001111011111011021222112 |
4 | 2200200301321111303133 |
5 | 2421210040130144411 |
6 | 35243131135104235 |
7 | 2215625304432242 |
oct | 240406171256337 |
9 | 43044144137875 |
10 | 11030313131231 |
11 | 3572a25226089 |
12 | 12a18b967207b |
13 | 620200633ab4 |
14 | 2a1c27411259 |
15 | 141dcca37b8b |
hex | a0831e55cdf |
11030313131231 has 8 divisors (see below), whose sum is σ = 11300347969344. Its totient is φ = 10760326046080.
The previous prime is 11030313131213. The next prime is 11030313131263. The reversal of 11030313131231 is 13213131303011.
11030313131231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11030313131231 - 218 = 11030312869087 is a prime.
It is a super-2 number, since 2×110303131312312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11030313131197 and 11030313131206.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11030313136231) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11470391 + ... + 12394776.
It is an arithmetic number, because the mean of its divisors is an integer number (1412543496168).
Almost surely, 211030313131231 is an apocalyptic number.
11030313131231 is a deficient number, since it is larger than the sum of its proper divisors (270034838113).
11030313131231 is a wasteful number, since it uses less digits than its factorization.
11030313131231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23876481.
The product of its (nonzero) digits is 486, while the sum is 23.
Adding to 11030313131231 its reverse (13213131303011), we get a palindrome (24243444434242).
The spelling of 11030313131231 in words is "eleven trillion, thirty billion, three hundred thirteen million, one hundred thirty-one thousand, two hundred thirty-one".
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