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11030541433 = 111730193271
BaseRepresentation
bin10100100010111100…
…01011010001111001
31001110201220120012121
422101132023101321
5140042304311213
65022314441241
7540230024632
oct122136132171
931421816177
1011030541433
1147504a904a
12217a133221
13106a35bbc2
14768d80889
154485c388d
hex29178b479

11030541433 has 8 divisors (see below), whose sum is σ = 11047449920. Its totient is φ = 11013647760.

The previous prime is 11030541397. The next prime is 11030541461. The reversal of 11030541433 is 33414503011.

11030541433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11030541433 - 229 = 10493670521 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11030541398 and 11030541407.

It is not an unprimeable number, because it can be changed into a prime (11030541493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3370588 + ... + 3373858.

It is an arithmetic number, because the mean of its divisors is an integer number (1380931240).

Almost surely, 211030541433 is an apocalyptic number.

It is an amenable number.

11030541433 is a deficient number, since it is larger than the sum of its proper divisors (16908487).

11030541433 is a wasteful number, since it uses less digits than its factorization.

11030541433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7407.

The product of its (nonzero) digits is 2160, while the sum is 25.

The spelling of 11030541433 in words is "eleven billion, thirty million, five hundred forty-one thousand, four hundred thirty-three".

Divisors: 1 1117 3019 3271 3372223 3653707 9875149 11030541433