Base | Representation |
---|---|
bin | 1010000010000110110101… |
… | …1100001101111111011101 |
3 | 1110001120202002221200200102 |
4 | 2200201231130031333131 |
5 | 2421214111401130023 |
6 | 35243414223110445 |
7 | 2215662124663160 |
oct | 240415534157735 |
9 | 43046662850612 |
10 | 11031312130013 |
11 | 357339812570a |
12 | 12a1b38142425 |
13 | 62032c5b0336 |
14 | 2a1cbdd7bad7 |
15 | 141e3a5bc628 |
hex | a086d70dfdd |
11031312130013 has 4 divisors (see below), whose sum is σ = 12607213862880. Its totient is φ = 9455410397148.
The previous prime is 11031312130009. The next prime is 11031312130043. The reversal of 11031312130013 is 31003121313011.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11031312130013 - 22 = 11031312130009 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11031312130043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 787950866423 + ... + 787950866436.
It is an arithmetic number, because the mean of its divisors is an integer number (3151803465720).
Almost surely, 211031312130013 is an apocalyptic number.
It is an amenable number.
11031312130013 is a deficient number, since it is larger than the sum of its proper divisors (1575901732867).
11031312130013 is an equidigital number, since it uses as much as digits as its factorization.
11031312130013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1575901732866.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 11031312130013 its reverse (31003121313011), we get a palindrome (42034433443024).
The spelling of 11031312130013 in words is "eleven trillion, thirty-one billion, three hundred twelve million, one hundred thirty thousand, thirteen".
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