Base | Representation |
---|---|
bin | 10100100011000111… |
… | …10010100011010101 |
3 | 1001110211200022211120 |
4 | 22101203302203111 |
5 | 140043143404023 |
6 | 5022410154153 |
7 | 540245364150 |
oct | 122143624325 |
9 | 31424608746 |
10 | 11032013013 |
11 | 475131372a |
12 | 217a722959 |
13 | 106a755968 |
14 | 769244c97 |
15 | 4487b48e3 |
hex | 2918f28d5 |
11032013013 has 8 divisors (see below), whose sum is σ = 16810686528. Its totient is φ = 6304007424.
The previous prime is 11032013011. The next prime is 11032013029. The reversal of 11032013013 is 31031023011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11032013013 - 21 = 11032013011 is a prime.
It is a super-2 number, since 2×110320130132 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11032012983 and 11032013001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11032013011) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 262666956 + ... + 262666997.
It is an arithmetic number, because the mean of its divisors is an integer number (2101335816).
Almost surely, 211032013013 is an apocalyptic number.
It is an amenable number.
11032013013 is a deficient number, since it is larger than the sum of its proper divisors (5778673515).
11032013013 is an equidigital number, since it uses as much as digits as its factorization.
11032013013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 525333963.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 11032013013 its reverse (31031023011), we get a palindrome (42063036024).
The spelling of 11032013013 in words is "eleven billion, thirty-two million, thirteen thousand, thirteen".
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