Base | Representation |
---|---|
bin | 1010000010001010101011… |
… | …1001001001100111010010 |
3 | 1110001200101221221122010222 |
4 | 2200202222321021213102 |
5 | 2421223214314440214 |
6 | 35244104412553042 |
7 | 2216026514203622 |
oct | 240425271114722 |
9 | 43050357848128 |
10 | 11032343124434 |
11 | 3573877099015 |
12 | 12a2185482782 |
13 | 62046507ccc8 |
14 | 2a1d7ac76882 |
15 | 141e9ad7238e |
hex | a08aae499d2 |
11032343124434 has 4 divisors (see below), whose sum is σ = 16548514686654. Its totient is φ = 5516171562216.
The previous prime is 11032343124409. The next prime is 11032343124457. The reversal of 11032343124434 is 43442134323011.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 7773585253225 + 3258757871209 = 2788115^2 + 1805203^2 .
It is a junction number, because it is equal to n+sod(n) for n = 11032343124394 and 11032343124403.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2758085781107 + ... + 2758085781110.
Almost surely, 211032343124434 is an apocalyptic number.
11032343124434 is a deficient number, since it is larger than the sum of its proper divisors (5516171562220).
11032343124434 is an equidigital number, since it uses as much as digits as its factorization.
11032343124434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5516171562219.
The product of its (nonzero) digits is 82944, while the sum is 35.
Adding to 11032343124434 its reverse (43442134323011), we get a palindrome (54474477447445).
The spelling of 11032343124434 in words is "eleven trillion, thirty-two billion, three hundred forty-three million, one hundred twenty-four thousand, four hundred thirty-four".
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