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110330001023 = 1110030000093
BaseRepresentation
bin110011011000000101…
…1100011011001111111
3101112210002100202200012
41212300023203121333
53301423440013043
6122403534453435
710654036351364
oct1466013433177
9345702322605
10110330001023
1142877455830
121947136427b
13a5339a0298
1454a8d6646b
152d0b080a18
hex19b02e367f

110330001023 has 4 divisors (see below), whose sum is σ = 120360001128. Its totient is φ = 100300000920.

The previous prime is 110330001013. The next prime is 110330001029. The reversal of 110330001023 is 320100033011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 110330001023 - 222 = 110325806719 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 110330000989 and 110330001007.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110330001029) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5015000036 + ... + 5015000057.

It is an arithmetic number, because the mean of its divisors is an integer number (30090000282).

Almost surely, 2110330001023 is an apocalyptic number.

110330001023 is a deficient number, since it is larger than the sum of its proper divisors (10030000105).

110330001023 is a wasteful number, since it uses less digits than its factorization.

110330001023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10030000104.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 110330001023 its reverse (320100033011), we get a palindrome (430430034034).

The spelling of 110330001023 in words is "one hundred ten billion, three hundred thirty million, one thousand, twenty-three".

Divisors: 1 11 10030000093 110330001023