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11033100314 = 25516550157
BaseRepresentation
bin10100100011001111…
…11100000000011010
31001110220201120022222
422101213330000122
5140043433202224
65022445344042
7540260543135
oct122147740032
931426646288
1011033100314
114751996625
12217ab68022
13106aa46832
1476944921c
1544892bb5e
hex2919fc01a

11033100314 has 4 divisors (see below), whose sum is σ = 16549650474. Its totient is φ = 5516550156.

The previous prime is 11033100301. The next prime is 11033100341. The reversal of 11033100314 is 41300133011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 41300133011 = 231795657957.

It can be written as a sum of positive squares in only one way, i.e., 10445862025 + 587238289 = 102205^2 + 24233^2 .

It is a junction number, because it is equal to n+sod(n) for n = 11033100292 and 11033100301.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2758275077 + ... + 2758275080.

Almost surely, 211033100314 is an apocalyptic number.

11033100314 is a deficient number, since it is larger than the sum of its proper divisors (5516550160).

11033100314 is an equidigital number, since it uses as much as digits as its factorization.

11033100314 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5516550159.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 11033100314 its reverse (41300133011), we get a palindrome (52333233325).

The spelling of 11033100314 in words is "eleven billion, thirty-three million, one hundred thousand, three hundred fourteen".

Divisors: 1 2 5516550157 11033100314