Base | Representation |
---|---|
bin | 1010000010001101100101… |
… | …0100010101010001100111 |
3 | 1110001202102020112201100002 |
4 | 2200203121110111101213 |
5 | 2421231313213031043 |
6 | 35244313555011515 |
7 | 2216055022435022 |
oct | 240433124252147 |
9 | 43052366481302 |
10 | 11033122002023 |
11 | 3574136812300 |
12 | 12a2362299b9b |
13 | 62055a548914 |
14 | 2a20124a41b9 |
15 | 141ee4425bb8 |
hex | a08d9515467 |
11033122002023 has 6 divisors (see below), whose sum is σ = 12127315919712. Its totient is φ = 10030110910820.
The previous prime is 11033122001989. The next prime is 11033122002031. The reversal of 11033122002023 is 32020022133011.
It is not a de Polignac number, because 11033122002023 - 26 = 11033122001959 is a prime.
It is a super-3 number, since 3×110331220020233 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11033122001986 and 11033122002004.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11033122002823) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 45591413111 + ... + 45591413352.
It is an arithmetic number, because the mean of its divisors is an integer number (2021219319952).
Almost surely, 211033122002023 is an apocalyptic number.
11033122002023 is a deficient number, since it is larger than the sum of its proper divisors (1094193917689).
11033122002023 is an equidigital number, since it uses as much as digits as its factorization.
11033122002023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 91182826485 (or 91182826474 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 11033122002023 its reverse (32020022133011), we get a palindrome (43053144135034).
The spelling of 11033122002023 in words is "eleven trillion, thirty-three billion, one hundred twenty-two million, two thousand, twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •