Search a number
-
+
1103330230441 = 7603145117747
BaseRepresentation
bin10000000011100011100…
…110110100000010101001
310220110212222111000001221
4100003203212310002221
5121034110014333231
62202510215542041
7142466360135125
oct20034346640251
93813788430057
101103330230441
11395a1317345a
121599bb08a921
1380074a1342a
143b5898b2585
151da78025d11
hex100e39b40a9

1103330230441 has 4 divisors (see below), whose sum is σ = 1103475355792. Its totient is φ = 1103185105092.

The previous prime is 1103330230427. The next prime is 1103330230487. The reversal of 1103330230441 is 1440320333011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1103330230441 - 233 = 1094740295849 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1103330230141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72551271 + ... + 72566476.

It is an arithmetic number, because the mean of its divisors is an integer number (275868838948).

Almost surely, 21103330230441 is an apocalyptic number.

It is an amenable number.

1103330230441 is a deficient number, since it is larger than the sum of its proper divisors (145125351).

1103330230441 is an equidigital number, since it uses as much as digits as its factorization.

1103330230441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 145125350.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1103330230441 its reverse (1440320333011), we get a palindrome (2543650563452).

The spelling of 1103330230441 in words is "one trillion, one hundred three billion, three hundred thirty million, two hundred thirty thousand, four hundred forty-one".

Divisors: 1 7603 145117747 1103330230441