Base | Representation |
---|---|
bin | 10000000011100011101… |
… | …011000001010000001101 |
3 | 10220110220001120000200101 |
4 | 100003203223001100031 |
5 | 121034110310130013 |
6 | 2202510255331101 |
7 | 142466402410021 |
oct | 20034353012015 |
9 | 3813801500611 |
10 | 1103331333133 |
11 | 395a13856977 |
12 | 1599bb520a91 |
13 | 8007500b303 |
14 | 3b589abc381 |
15 | 1da781928dd |
hex | 100e3ac140d |
1103331333133 has 4 divisors (see below), whose sum is σ = 1103333727100. Its totient is φ = 1103328939168.
The previous prime is 1103331333031. The next prime is 1103331333149. The reversal of 1103331333133 is 3313331333011.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 15905749924 + 1087425583209 = 126118^2 + 1042797^2 .
It is a cyclic number.
It is not a de Polignac number, because 1103331333133 - 225 = 1103297778701 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1103331333233) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 262458 + ... + 1508491.
It is an arithmetic number, because the mean of its divisors is an integer number (275833431775).
Almost surely, 21103331333133 is an apocalyptic number.
It is an amenable number.
1103331333133 is a deficient number, since it is larger than the sum of its proper divisors (2393967).
1103331333133 is an equidigital number, since it uses as much as digits as its factorization.
1103331333133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2393966.
The product of its (nonzero) digits is 6561, while the sum is 28.
Adding to 1103331333133 its reverse (3313331333011), we get a palindrome (4416662666144).
The spelling of 1103331333133 in words is "one trillion, one hundred three billion, three hundred thirty-one million, three hundred thirty-three thousand, one hundred thirty-three".
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