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1103340121111 = 3006313670081
BaseRepresentation
bin10000000011100100001…
…100100010110000010111
310220110220200002111112001
4100003210030202300113
5121034120032333421
62202511211540131
7142466540200654
oct20034414426027
93813820074461
101103340121111
11395a18809468
12159a0245a647
1380076a972b7
143b58ad28c2b
151da78d2b691
hex100e4322c17

1103340121111 has 4 divisors (see below), whose sum is σ = 1103344091824. Its totient is φ = 1103336150400.

The previous prime is 1103340121097. The next prime is 1103340121127. The reversal of 1103340121111 is 1111210433011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1103340121111 - 219 = 1103339596823 is a prime.

It is a super-2 number, since 2×11033401211112 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1103340121171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1534410 + ... + 2135671.

It is an arithmetic number, because the mean of its divisors is an integer number (275836022956).

Almost surely, 21103340121111 is an apocalyptic number.

1103340121111 is a deficient number, since it is larger than the sum of its proper divisors (3970713).

1103340121111 is an equidigital number, since it uses as much as digits as its factorization.

1103340121111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3970712.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 1103340121111 its reverse (1111210433011), we get a palindrome (2214550554122).

The spelling of 1103340121111 in words is "one trillion, one hundred three billion, three hundred forty million, one hundred twenty-one thousand, one hundred eleven".

Divisors: 1 300631 3670081 1103340121111