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1103340321313 = 1958070543227
BaseRepresentation
bin10000000011100100001…
…101010011101000100001
310220110220200110200010221
4100003210031103220201
5121034120110240223
62202511220123041
7142466541663436
oct20034415235041
93813820420127
101103340321313
11395a1893591a
12159a02536481
1380076b37469
143b58ad7bb8d
151da78d6ab5d
hex100e4353a21

1103340321313 has 4 divisors (see below), whose sum is σ = 1161410864560. Its totient is φ = 1045269778068.

The previous prime is 1103340321233. The next prime is 1103340321341. The reversal of 1103340321313 is 3131230433011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1103340321313 - 29 = 1103340320801 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1103340351313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29035271595 + ... + 29035271632.

It is an arithmetic number, because the mean of its divisors is an integer number (290352716140).

Almost surely, 21103340321313 is an apocalyptic number.

It is an amenable number.

1103340321313 is a deficient number, since it is larger than the sum of its proper divisors (58070543247).

1103340321313 is an equidigital number, since it uses as much as digits as its factorization.

1103340321313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58070543246.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 1103340321313 its reverse (3131230433011), we get a palindrome (4234570754324).

The spelling of 1103340321313 in words is "one trillion, one hundred three billion, three hundred forty million, three hundred twenty-one thousand, three hundred thirteen".

Divisors: 1 19 58070543227 1103340321313