Base | Representation |
---|---|
bin | 110011011000011011… |
… | …0110100110001100001 |
3 | 101112210212201001210112 |
4 | 1212300312310301201 |
5 | 3301434341004403 |
6 | 122405021541105 |
7 | 10654234644332 |
oct | 1466066646141 |
9 | 345725631715 |
10 | 110341344353 |
11 | 428828a3189 |
12 | 19475114795 |
13 | a536142406 |
14 | 54aa67a289 |
15 | 2d0c0719d8 |
hex | 19b0db4c61 |
110341344353 has 4 divisors (see below), whose sum is σ = 110342150400. Its totient is φ = 110340538308.
The previous prime is 110341344331. The next prime is 110341344383. The reversal of 110341344353 is 353443143011.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 110341344353 - 224 = 110324567137 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (110341344383) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 140825 + ... + 490422.
It is an arithmetic number, because the mean of its divisors is an integer number (27585537600).
Almost surely, 2110341344353 is an apocalyptic number.
It is an amenable number.
110341344353 is a deficient number, since it is larger than the sum of its proper divisors (806047).
110341344353 is an equidigital number, since it uses as much as digits as its factorization.
110341344353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 806046.
The product of its (nonzero) digits is 25920, while the sum is 32.
Adding to 110341344353 its reverse (353443143011), we get a palindrome (463784487364).
The spelling of 110341344353 in words is "one hundred ten billion, three hundred forty-one million, three hundred forty-four thousand, three hundred fifty-three".
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