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11034402020114 = 211501563728187
BaseRepresentation
bin1010000010010010010110…
…0111001101101100010010
31110001212201110010101001112
42200210211213031230102
52421241423404120424
635245045002133322
72216131524423134
oct240444547155422
943055643111045
1011034402020114
1135747333018a0
1212a265aab1242
136207027a8785
142a20d44a3054
1514206b9ba60e
hexa09259cdb12

11034402020114 has 8 divisors (see below), whose sum is σ = 18056294214768. Its totient is φ = 5015637281860.

The previous prime is 11034402020111. The next prime is 11034402020137. The reversal of 11034402020114 is 41102020443011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a self number, because there is not a number n which added to its sum of digits gives 11034402020114.

It is not an unprimeable number, because it can be changed into a prime (11034402020111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 250781864072 + ... + 250781864115.

It is an arithmetic number, because the mean of its divisors is an integer number (2257036776846).

Almost surely, 211034402020114 is an apocalyptic number.

11034402020114 is a deficient number, since it is larger than the sum of its proper divisors (7021892194654).

11034402020114 is a wasteful number, since it uses less digits than its factorization.

11034402020114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 501563728200.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 11034402020114 its reverse (41102020443011), we get a palindrome (52136422463125).

The spelling of 11034402020114 in words is "eleven trillion, thirty-four billion, four hundred two million, twenty thousand, one hundred fourteen".

Divisors: 1 2 11 22 501563728187 1003127456374 5517201010057 11034402020114