1103540240131 has 4 divisors (see below), whose sum is σ = 1261188845872. Its totient is φ = 945891634392.

The previous prime is 1103540240123. The next prime is 1103540240137. The reversal of 1103540240131 is 1310420453011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1103540240131 - 2³ = 1103540240123 is a prime.

It is a super-2 number, since 2×1103540240131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1103540240096 and 1103540240105.

It is not an unprimeable number, because it can be changed into a prime (1103540240137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 78824302860 + ... + 78824302873.

It is an arithmetic number, because the mean of its divisors is an integer number (315297211468).

Almost surely, 2^{1103540240131} is an apocalyptic number.

1103540240131 is a deficient number, since it is larger than the sum of its proper divisors (157648605741).

1103540240131 is an equidigital number, since it uses as much as digits as its factorization.

1103540240131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 157648605740.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 1103540240131 its reverse (1310420453011), we get a palindrome (2413960693142).

The spelling of 1103540240131 in words is "one trillion, one hundred three billion, five hundred forty million, two hundred forty thousand, one hundred thirty-one".