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11040014103 = 33680004701
BaseRepresentation
bin10100100100000100…
…10011111100010111
31001111101201211021020
422102002103330113
5140102220422403
65023253452223
7540403400016
oct122202237427
931441654236
1011040014103
114755888aa8
122181341073
13106c2c7731
1476a328a7d
15449345453
hex292093f17

11040014103 has 4 divisors (see below), whose sum is σ = 14720018808. Its totient is φ = 7360009400.

The previous prime is 11040014101. The next prime is 11040014107. The reversal of 11040014103 is 30141004011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30141004011 = 310047001337.

It is a cyclic number.

It is not a de Polignac number, because 11040014103 - 21 = 11040014101 is a prime.

It is a super-2 number, since 2×110400141032 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11040014101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1840002348 + ... + 1840002353.

It is an arithmetic number, because the mean of its divisors is an integer number (3680004702).

Almost surely, 211040014103 is an apocalyptic number.

11040014103 is a deficient number, since it is larger than the sum of its proper divisors (3680004705).

11040014103 is an equidigital number, since it uses as much as digits as its factorization.

11040014103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3680004704.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 11040014103 its reverse (30141004011), we get a palindrome (41181018114).

The spelling of 11040014103 in words is "eleven billion, forty million, fourteen thousand, one hundred three".

Divisors: 1 3 3680004701 11040014103