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11040100133 = 105311048343
BaseRepresentation
bin10100100100000101…
…01000111100100101
31001111101220012021112
422102002220330211
5140102231201013
65023255354405
7540404205566
oct122202507445
931441805245
1011040100133
1147559376a7
122181382a05
13106c32793a
1476a34c16d
15449360ba8
hex2920a8f25

11040100133 has 4 divisors (see below), whose sum is σ = 11041159008. Its totient is φ = 11039041260.

The previous prime is 11040100087. The next prime is 11040100147. The reversal of 11040100133 is 33100104011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11040100133 - 220 = 11039051557 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11040100163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 513641 + ... + 534702.

It is an arithmetic number, because the mean of its divisors is an integer number (2760289752).

Almost surely, 211040100133 is an apocalyptic number.

It is an amenable number.

11040100133 is a deficient number, since it is larger than the sum of its proper divisors (1058875).

11040100133 is a wasteful number, since it uses less digits than its factorization.

11040100133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1058874.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 11040100133 its reverse (33100104011), we get a palindrome (44140204144).

The spelling of 11040100133 in words is "eleven billion, forty million, one hundred thousand, one hundred thirty-three".

Divisors: 1 10531 1048343 11040100133