1104011031331 has 4 divisors (see below), whose sum is σ = 1188934956832. Its totient is φ = 1019087105832.

The previous prime is 1104011031313. The next prime is 1104011031349. The reversal of 1104011031331 is 1331301104011.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1104011031313) and next prime (1104011031349).

It is a cyclic number.

It is not a de Polignac number, because 1104011031331 - 2³⁹ = 554255217443 is a prime.

It is a super-2 number, since 2×1104011031331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1104011031299 and 1104011031308.

It is not an unprimeable number, because it can be changed into a prime (1104011031131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42461962731 + ... + 42461962756.

It is an arithmetic number, because the mean of its divisors is an integer number (297233739208).

Almost surely, 2^{1104011031331} is an apocalyptic number.

1104011031331 is a deficient number, since it is larger than the sum of its proper divisors (84923925501).

1104011031331 is an equidigital number, since it uses as much as digits as its factorization.

1104011031331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 84923925500.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 1104011031331 its reverse (1331301104011), we get a palindrome (2435312135342).

The spelling of 1104011031331 in words is "one trillion, one hundred four billion, eleven million, thirty-one thousand, three hundred thirty-one".