Base | Representation |
---|---|
bin | 10100100100000110… |
… | …00010110000111011 |
3 | 1001111102002120100012 |
4 | 22102003002300323 |
5 | 140102243042013 |
6 | 5023301532135 |
7 | 540405126110 |
oct | 122203026073 |
9 | 31442076305 |
10 | 11040205883 |
11 | 47559aa0a3 |
12 | 218141404b |
13 | 106c363b05 |
14 | 76a378907 |
15 | 4493821a8 |
hex | 2920c2c3b |
11040205883 has 4 divisors (see below), whose sum is σ = 12617378160. Its totient is φ = 9463033608.
The previous prime is 11040205879. The next prime is 11040205973. The reversal of 11040205883 is 38850204011.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 11040205883 - 22 = 11040205879 is a prime.
It is a super-2 number, since 2×110402058832 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11040205783) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 788586128 + ... + 788586141.
It is an arithmetic number, because the mean of its divisors is an integer number (3154344540).
Almost surely, 211040205883 is an apocalyptic number.
11040205883 is a deficient number, since it is larger than the sum of its proper divisors (1577172277).
11040205883 is an equidigital number, since it uses as much as digits as its factorization.
11040205883 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1577172276.
The product of its (nonzero) digits is 7680, while the sum is 32.
Adding to 11040205883 its reverse (38850204011), we get a palindrome (49890409894).
The spelling of 11040205883 in words is "eleven billion, forty million, two hundred five thousand, eight hundred eighty-three".
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