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11040425543613 = 39803375409757
BaseRepresentation
bin1010000010101000110010…
…1001001000011110111101
31110002110021020110001220110
42200222030221020132331
52421341242414343423
635251522415140233
72216434015504134
oct240521451103675
943073236401813
1011040425543613
11357724443a194
1212a3860214679
136211526bc66b
142a250647691b
151422c06ed193
hexa0a8ca487bd

11040425543613 has 8 divisors (see below), whose sum is σ = 14722069069728. Its totient is φ = 7359532856624.

The previous prime is 11040425543599. The next prime is 11040425543657. The reversal of 11040425543613 is 31634552404011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11040425543613 - 24 = 11040425543597 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11040425563613) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 187675470 + ... + 187734287.

It is an arithmetic number, because the mean of its divisors is an integer number (1840258633716).

Almost surely, 211040425543613 is an apocalyptic number.

It is an amenable number.

11040425543613 is a deficient number, since it is larger than the sum of its proper divisors (3681643526115).

11040425543613 is an equidigital number, since it uses as much as digits as its factorization.

11040425543613 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 375419563.

The product of its (nonzero) digits is 172800, while the sum is 39.

Adding to 11040425543613 its reverse (31634552404011), we get a palindrome (42674977947624).

The spelling of 11040425543613 in words is "eleven trillion, forty billion, four hundred twenty-five million, five hundred forty-three thousand, six hundred thirteen".

Divisors: 1 3 9803 29409 375409757 1126229271 3680141847871 11040425543613