1104113132301 has 4 divisors (see below), whose sum is σ = 1472150843072. Its totient is φ = 736075421532.

The previous prime is 1104113132293. The next prime is 1104113132323. The reversal of 1104113132301 is 1032313114011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1104113132301 - 2³ = 1104113132293 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1104113132371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 184018855381 + ... + 184018855386.

It is an arithmetic number, because the mean of its divisors is an integer number (368037710768).

Almost surely, 2^{1104113132301} is an apocalyptic number.

It is an amenable number.

1104113132301 is a deficient number, since it is larger than the sum of its proper divisors (368037710771).

1104113132301 is an equidigital number, since it uses as much as digits as its factorization.

1104113132301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 368037710770.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 1104113132301 its reverse (1032313114011), we get a palindrome (2136426246312).

The spelling of 1104113132301 in words is "one trillion, one hundred four billion, one hundred thirteen million, one hundred thirty-two thousand, three hundred one".