Base | Representation |
---|---|
bin | 110011011010100000… |
… | …1110011001000000101 |
3 | 101112222202101201010111 |
4 | 1212311001303020011 |
5 | 3302110300030203 |
6 | 122420001553021 |
7 | 10656044551303 |
oct | 1466501631005 |
9 | 345882351114 |
10 | 110411330053 |
11 | 42909354502 |
12 | 19494645771 |
13 | a5477a757b |
14 | 54b5a97273 |
15 | 2d1329826d |
hex | 19b5073205 |
110411330053 has 4 divisors (see below), whose sum is σ = 115211822688. Its totient is φ = 105610837420.
The previous prime is 110411330041. The next prime is 110411330069. The reversal of 110411330053 is 350033114011.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 110411330053 - 213 = 110411321861 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (110411337053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2400246283 + ... + 2400246328.
It is an arithmetic number, because the mean of its divisors is an integer number (28802955672).
Almost surely, 2110411330053 is an apocalyptic number.
It is an amenable number.
110411330053 is a deficient number, since it is larger than the sum of its proper divisors (4800492635).
110411330053 is an equidigital number, since it uses as much as digits as its factorization.
110411330053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4800492634.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 110411330053 its reverse (350033114011), we get a palindrome (460444444064).
The spelling of 110411330053 in words is "one hundred ten billion, four hundred eleven million, three hundred thirty thousand, fifty-three".
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