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110414342113 = 331333327601
BaseRepresentation
bin110011011010100110…
…1010010011111100001
3101112222222001201220021
41212311031102133201
53302112032421423
6122420150313441
710656112264645
oct1466515223741
9345888051807
10110414342113
1142910021509
1219495658881
13a5482c055a
1454b623cc25
152d1369095d
hex19b53527e1

110414342113 has 4 divisors (see below), whose sum is σ = 110447673028. Its totient is φ = 110381011200.

The previous prime is 110414342057. The next prime is 110414342183. The reversal of 110414342113 is 311243414011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311243414011 = 2272113698491.

It can be written as a sum of positive squares in 2 ways, for example, as 46598993424 + 63815348689 = 215868^2 + 252617^2 .

It is a cyclic number.

It is not a de Polignac number, because 110414342113 - 213 = 110414333921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (110414342183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16660488 + ... + 16667113.

It is an arithmetic number, because the mean of its divisors is an integer number (27611918257).

Almost surely, 2110414342113 is an apocalyptic number.

It is an amenable number.

110414342113 is a deficient number, since it is larger than the sum of its proper divisors (33330915).

110414342113 is an equidigital number, since it uses as much as digits as its factorization.

110414342113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33330914.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 110414342113 its reverse (311243414011), we get a palindrome (421657756124).

The spelling of 110414342113 in words is "one hundred ten billion, four hundred fourteen million, three hundred forty-two thousand, one hundred thirteen".

Divisors: 1 3313 33327601 110414342113