1104213000031 has 4 divisors (see below), whose sum is σ = 1131145024464. Its totient is φ = 1077280975600.

The previous prime is 1104213000019. The next prime is 1104213000067. The reversal of 1104213000031 is 1300003124011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1104213000031 - 2¹¹ = 1104212997983 is a prime.

It is a super-2 number, since 2×1104213000031² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1104212999969 and 1104213000014.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1104213000071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13466012155 + ... + 13466012236.

It is an arithmetic number, because the mean of its divisors is an integer number (282786256116).

Almost surely, 2^{1104213000031} is an apocalyptic number.

1104213000031 is a deficient number, since it is larger than the sum of its proper divisors (26932024433).

1104213000031 is an equidigital number, since it uses as much as digits as its factorization.

1104213000031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26932024432.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1104213000031 its reverse (1300003124011), we get a palindrome (2404216124042).

The spelling of 1104213000031 in words is "one trillion, one hundred four billion, two hundred thirteen million, thirty-one", and thus it is an aban number.