Base | Representation |
---|---|
bin | 10100100100011100… |
… | …01101000101101001 |
3 | 1001111121121012212202 |
4 | 22102032031011221 |
5 | 140104020204003 |
6 | 5023444345545 |
7 | 540442033253 |
oct | 122216150551 |
9 | 31447535782 |
10 | 11043131753 |
11 | 4757618375 |
12 | 21823a52b5 |
13 | 106cb497b4 |
14 | 76a8dacd3 |
15 | 44975e088 |
hex | 29238d169 |
11043131753 has 4 divisors (see below), whose sum is σ = 11048360148. Its totient is φ = 11037903360.
The previous prime is 11043131741. The next prime is 11043131831. The reversal of 11043131753 is 35713134011.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 129777664 + 10913354089 = 11392^2 + 104467^2 .
It is a cyclic number.
It is not a de Polignac number, because 11043131753 - 216 = 11043066217 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11043131153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2611028 + ... + 2615253.
It is an arithmetic number, because the mean of its divisors is an integer number (2762090037).
Almost surely, 211043131753 is an apocalyptic number.
It is an amenable number.
11043131753 is a deficient number, since it is larger than the sum of its proper divisors (5228395).
11043131753 is an equidigital number, since it uses as much as digits as its factorization.
11043131753 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5228394.
The product of its (nonzero) digits is 3780, while the sum is 29.
Adding to 11043131753 its reverse (35713134011), we get a palindrome (46756265764).
The spelling of 11043131753 in words is "eleven billion, forty-three million, one hundred thirty-one thousand, seven hundred fifty-three".
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