1104330413111 has 4 divisors (see below), whose sum is σ = 1123047877800. Its totient is φ = 1085612948424.

The previous prime is 1104330413071. The next prime is 1104330413113. The reversal of 1104330413111 is 1113140334011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1104330413111 - 2¹⁴ = 1104330396727 is a prime.

It is a super-2 number, since 2×1104330413111² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1104330413113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9358732256 + ... + 9358732373.

It is an arithmetic number, because the mean of its divisors is an integer number (280761969450).

Almost surely, 2^{1104330413111} is an apocalyptic number.

1104330413111 is a deficient number, since it is larger than the sum of its proper divisors (18717464689).

1104330413111 is an equidigital number, since it uses as much as digits as its factorization.

1104330413111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18717464688.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 1104330413111 its reverse (1113140334011), we get a palindrome (2217470747122).

The spelling of 1104330413111 in words is "one trillion, one hundred four billion, three hundred thirty million, four hundred thirteen thousand, one hundred eleven".