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1104331211323 = 1278695521349
BaseRepresentation
bin10000000100011111010…
…001010000001000111011
310220120110202000002200221
4100010133101100020323
5121043132242230243
62203153414240511
7142533233262544
oct20043721201073
93816422002627
101104331211323
113963871a718a
1215a03a356137
13801a4204c02
143b6427d74cb
151dad5d4cbed
hex1011f45023b

1104331211323 has 4 divisors (see below), whose sum is σ = 1113026732800. Its totient is φ = 1095635689848.

The previous prime is 1104331211239. The next prime is 1104331211351. The reversal of 1104331211323 is 3231121334011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1104331211323 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1104331211383) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4347760548 + ... + 4347760801.

It is an arithmetic number, because the mean of its divisors is an integer number (278256683200).

Almost surely, 21104331211323 is an apocalyptic number.

1104331211323 is a deficient number, since it is larger than the sum of its proper divisors (8695521477).

1104331211323 is an equidigital number, since it uses as much as digits as its factorization.

1104331211323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8695521476.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1104331211323 its reverse (3231121334011), we get a palindrome (4335452545334).

The spelling of 1104331211323 in words is "one trillion, one hundred four billion, three hundred thirty-one million, two hundred eleven thousand, three hundred twenty-three".

Divisors: 1 127 8695521349 1104331211323