Base | Representation |
---|---|
bin | 1010000010110011101111… |
… | …1010111011011011110001 |
3 | 1110002201212011211222200020 |
4 | 2200230323322323123301 |
5 | 2421413303223042203 |
6 | 35253130304114053 |
7 | 2216566624035201 |
oct | 240547372733361 |
9 | 43081764758606 |
10 | 11043366221553 |
11 | 3578513372036 |
12 | 12a4341005929 |
13 | 621500a03693 |
14 | 2a2704c3a401 |
15 | 1423e3975153 |
hex | a0b3bebb6f1 |
11043366221553 has 16 divisors (see below), whose sum is σ = 14744169221760. Its totient is φ = 7352404504704.
The previous prime is 11043366221497. The next prime is 11043366221593. The reversal of 11043366221553 is 35512266334011.
It is a happy number.
It is not a de Polignac number, because 11043366221553 - 220 = 11043365172977 is a prime.
It is a super-3 number, since 3×110433662215533 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (11043366221593) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 62150925 + ... + 62328357.
It is an arithmetic number, because the mean of its divisors is an integer number (921510576360).
Almost surely, 211043366221553 is an apocalyptic number.
It is an amenable number.
11043366221553 is a deficient number, since it is larger than the sum of its proper divisors (3700803000207).
11043366221553 is a wasteful number, since it uses less digits than its factorization.
11043366221553 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 205048.
The product of its (nonzero) digits is 388800, while the sum is 42.
The spelling of 11043366221553 in words is "eleven trillion, forty-three billion, three hundred sixty-six million, two hundred twenty-one thousand, five hundred fifty-three".
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