Base | Representation |
---|---|
bin | 1010000010110110001110… |
… | …1011101010110110110011 |
3 | 1110002210120200002121011121 |
4 | 2200231203223222312303 |
5 | 2421421140011411011 |
6 | 35253320414123111 |
7 | 2216622304143643 |
oct | 240554353526663 |
9 | 43083520077147 |
10 | 11044033310131 |
11 | 3578825982608 |
12 | 12a44a84b0497 |
13 | 6215a8c8b853 |
14 | 2a2769688523 |
15 | 1424322e5e71 |
hex | a0b63aeadb3 |
11044033310131 has 16 divisors (see below), whose sum is σ = 11715366312000. Its totient is φ = 10375116064768.
The previous prime is 11044033310077. The next prime is 11044033310137. The reversal of 11044033310131 is 13101333044011.
It is a cyclic number.
It is not a de Polignac number, because 11044033310131 - 225 = 11043999755699 is a prime.
It is a super-2 number, since 2×110440333101312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11044033310096 and 11044033310105.
It is not an unprimeable number, because it can be changed into a prime (11044033310137) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 56652555 + ... + 56847163.
It is an arithmetic number, because the mean of its divisors is an integer number (732210394500).
Almost surely, 211044033310131 is an apocalyptic number.
11044033310131 is a deficient number, since it is larger than the sum of its proper divisors (671333001869).
11044033310131 is a wasteful number, since it uses less digits than its factorization.
11044033310131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 200798.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 11044033310131 its reverse (13101333044011), we get a palindrome (24145366354142).
The spelling of 11044033310131 in words is "eleven trillion, forty-four billion, thirty-three million, three hundred ten thousand, one hundred thirty-one".
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