1104414433 has 4 divisors (see below), whose sum is σ = 1104524548. Its totient is φ = 1104304320.

The previous prime is 1104414407. The next prime is 1104414449. The reversal of 1104414433 is 3344144011.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3344144011 = 13 ⋅257241847.

It can be written as a sum of positive squares in 2 ways, for example, as 233692369 + 870722064 = 15287^2 + 29508^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1104414433 is a prime.

It is a super-2 number, since 2×1104414433² = 2439462479637422978, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1104414398 and 1104414407.

It is not an unprimeable number, because it can be changed into a prime (1104414833) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38316 + ... + 60637.

It is an arithmetic number, because the mean of its divisors is an integer number (276131137).

Almost surely, 2^1104414433 is an apocalyptic number.

It is an amenable number.

1104414433 is a deficient number, since it is larger than the sum of its proper divisors (110115).

1104414433 is an equidigital number, since it uses as much as digits as its factorization.

1104414433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 110114.

The product of its (nonzero) digits is 2304, while the sum is 25.

The square root of 1104414433 is about 33232.7313502818. The cubic root of 1104414433 is about 1033.6591606450.

Adding to 1104414433 its reverse (3344144011), we get a palindrome (4448558444).

The spelling of 1104414433 in words is "one billion, one hundred four million, four hundred fourteen thousand, four hundred thirty-three".