11044213441 has 4 divisors (see below), whose sum is σ = 11086206912. Its totient is φ = 11002219972.

The previous prime is 11044213399. The next prime is 11044213459. The reversal of 11044213441 is 14431244011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11044213441 - 2¹¹ = 11044211393 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11044213471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20996341 + ... + 20996866.

It is an arithmetic number, because the mean of its divisors is an integer number (2771551728).

Almost surely, 2^11044213441 is an apocalyptic number.

It is an amenable number.

11044213441 is a deficient number, since it is larger than the sum of its proper divisors (41993471).

11044213441 is an equidigital number, since it uses as much as digits as its factorization.

11044213441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41993470.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 11044213441 its reverse (14431244011), we get a palindrome (25475457452).

The spelling of 11044213441 in words is "eleven billion, forty-four million, two hundred thirteen thousand, four hundred forty-one".