11044300013 has 4 divisors (see below), whose sum is σ = 11195591868. Its totient is φ = 10893008160.

The previous prime is 11044300009. The next prime is 11044300021. The reversal of 11044300013 is 31000344011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3113863204 + 7930436809 = 55802^2 + 89053^2 .

It is a cyclic number.

It is not a de Polignac number, because 11044300013 - 2² = 11044300009 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11044299964 and 11044300000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11044300313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75645818 + ... + 75645963.

It is an arithmetic number, because the mean of its divisors is an integer number (2798897967).

Almost surely, 2^11044300013 is an apocalyptic number.

It is an amenable number.

11044300013 is a deficient number, since it is larger than the sum of its proper divisors (151291855).

11044300013 is an equidigital number, since it uses as much as digits as its factorization.

11044300013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 151291854.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 11044300013 its reverse (31000344011), we get a palindrome (42044644024).

The spelling of 11044300013 in words is "eleven billion, forty-four million, three hundred thousand, thirteen".